Base | Representation |
---|---|
bin | 11101110011110011010010… |
… | …011110101011010101000001 |
3 | 122012012100001100201212001101 |
4 | 131303303102132223111001 |
5 | 114140443133412002012 |
6 | 1142455534425534401 |
7 | 36420613233410506 |
oct | 3563632236532501 |
9 | 565170040655041 |
10 | 131103113000257 |
11 | 3885657748a402 |
12 | 128547b3344401 |
13 | 581cc8028a838 |
14 | 24535d2c854ad |
15 | 102545d4aed57 |
hex | 773cd27ab541 |
131103113000257 has 2 divisors, whose sum is σ = 131103113000258. Its totient is φ = 131103113000256.
The previous prime is 131103113000173. The next prime is 131103113000281. The reversal of 131103113000257 is 752000311301131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70216288394256 + 60886824606001 = 8379516^2 + 7803001^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131103113000257 is a prime.
It is not a weakly prime, because it can be changed into another prime (131103113010257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551556500128 + 65551556500129.
It is an arithmetic number, because the mean of its divisors is an integer number (65551556500129).
Almost surely, 2131103113000257 is an apocalyptic number.
It is an amenable number.
131103113000257 is a deficient number, since it is larger than the sum of its proper divisors (1).
131103113000257 is an equidigital number, since it uses as much as digits as its factorization.
131103113000257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1890, while the sum is 28.
Adding to 131103113000257 its reverse (752000311301131), we get a palindrome (883103424301388).
The spelling of 131103113000257 in words is "one hundred thirty-one trillion, one hundred three billion, one hundred thirteen million, two hundred fifty-seven", and thus it is an aban number.
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