Search a number
-
+
13110320234114 = 26555160117057
BaseRepresentation
bin1011111011000111101111…
…1110101111111010000010
31201102100000202111002021022
42332301323332233322002
53204244413434442424
643514444210025442
72522121646204115
oct276617376577202
951370022432238
1013110320234114
1141a5067a944a4
121578a4b878282
137413b4618c5c
1433478596857c
1517b06993895e
hexbec7bfafe82

13110320234114 has 4 divisors (see below), whose sum is σ = 19665480351174. Its totient is φ = 6555160117056.

The previous prime is 13110320234057. The next prime is 13110320234173. The reversal of 13110320234114 is 41143202301131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13106391075625 + 3929158489 = 3620275^2 + 62683^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277580058527 + ... + 3277580058530.

Almost surely, 213110320234114 is an apocalyptic number.

13110320234114 is a deficient number, since it is larger than the sum of its proper divisors (6555160117060).

13110320234114 is an equidigital number, since it uses as much as digits as its factorization.

13110320234114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6555160117059.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 13110320234114 its reverse (41143202301131), we get a palindrome (54253522535245).

The spelling of 13110320234114 in words is "thirteen trillion, one hundred ten billion, three hundred twenty million, two hundred thirty-four thousand, one hundred fourteen".

Divisors: 1 2 6555160117057 13110320234114