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13110324134002 = 231211456840871
BaseRepresentation
bin1011111011000111110000…
…1101101000000001110010
31201102100001000211012220121
42332301330031220001302
53204244420434242002
643514444425400454
72522122024306054
oct276617415500162
951370030735817
1013110324134002
1141a506a208547
121578a5103912a
137413b5383094
143347862a18d4
1517b069e59237
hexbec7c368072

13110324134002 has 8 divisors (see below), whose sum is σ = 20299856723712. Its totient is φ = 6343705226100.

The previous prime is 13110324133997. The next prime is 13110324134003. The reversal of 13110324134002 is 20043142301131.

13110324134002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not an unprimeable number, because it can be changed into a prime (13110324134003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105728420374 + ... + 105728420497.

It is an arithmetic number, because the mean of its divisors is an integer number (2537482090464).

Almost surely, 213110324134002 is an apocalyptic number.

13110324134002 is a deficient number, since it is larger than the sum of its proper divisors (7189532589710).

13110324134002 is a wasteful number, since it uses less digits than its factorization.

13110324134002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211456840904.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13110324134002 its reverse (20043142301131), we get a palindrome (33153466435133).

The spelling of 13110324134002 in words is "thirteen trillion, one hundred ten billion, three hundred twenty-four million, one hundred thirty-four thousand, two".

Divisors: 1 2 31 62 211456840871 422913681742 6555162067001 13110324134002