Base | Representation |
---|---|
bin | 11000011010110111… |
… | …11100011111100011 |
3 | 1020211200101211122021 |
4 | 30031123330133203 |
5 | 203322221100423 |
6 | 10004531522311 |
7 | 642612656263 |
oct | 141533743743 |
9 | 36750354567 |
10 | 13110331363 |
11 | 5618492aa8 |
12 | 265a759397 |
13 | 130c1c1b2c |
14 | 8c52897a3 |
15 | 51ae9795d |
hex | 30d6fc7e3 |
13110331363 has 2 divisors, whose sum is σ = 13110331364. Its totient is φ = 13110331362.
The previous prime is 13110331309. The next prime is 13110331433. The reversal of 13110331363 is 36313301131.
It is a weak prime.
It is an emirp because it is prime and its reverse (36313301131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13110331363 - 217 = 13110200291 is a prime.
It is a super-2 number, since 2×131103313632 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13110331063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555165681 + 6555165682.
It is an arithmetic number, because the mean of its divisors is an integer number (6555165682).
Almost surely, 213110331363 is an apocalyptic number.
13110331363 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110331363 is an equidigital number, since it uses as much as digits as its factorization.
13110331363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13110331363 its reverse (36313301131), we get a palindrome (49423632494).
The spelling of 13110331363 in words is "thirteen billion, one hundred ten million, three hundred thirty-one thousand, three hundred sixty-three".
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