Base | Representation |
---|---|
bin | 10011000100111111101… |
… | …111001000001001001011 |
3 | 11122100000020102012120222 |
4 | 103010333233020021023 |
5 | 132434444243002021 |
6 | 2442140355540255 |
7 | 163501440024500 |
oct | 23047757101113 |
9 | 4570006365528 |
10 | 1311034344011 |
11 | 466008788167 |
12 | 1921068ba68b |
13 | 96826188092 |
14 | 47650c394a7 |
15 | 241829ea6ab |
hex | 1313fbc824b |
1311034344011 has 12 divisors (see below), whose sum is σ = 1534794666768. Its totient is φ = 1116586113552.
The previous prime is 1311034343989. The next prime is 1311034344019. The reversal of 1311034344011 is 1104434301131.
It is a de Polignac number, because none of the positive numbers 2k-1311034344011 is a prime.
It is a super-2 number, since 2×13110343440112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1311034344019) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 85201871 + ... + 85217256.
It is an arithmetic number, because the mean of its divisors is an integer number (127899555564).
Almost surely, 21311034344011 is an apocalyptic number.
1311034344011 is a deficient number, since it is larger than the sum of its proper divisors (223760322757).
1311034344011 is a wasteful number, since it uses less digits than its factorization.
1311034344011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170419298 (or 170419291 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 1311034344011 its reverse (1104434301131), we get a palindrome (2415468645142).
The spelling of 1311034344011 in words is "one trillion, three hundred eleven billion, thirty-four million, three hundred forty-four thousand, eleven".
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