Base | Representation |
---|---|
bin | 10011000100111111101… |
… | …111011000010101000011 |
3 | 11122100000020112120112101 |
4 | 103010333233120111003 |
5 | 132434444302112212 |
6 | 2442140401211231 |
7 | 163501440421666 |
oct | 23047757302503 |
9 | 4570006476471 |
10 | 1311034410307 |
11 | 466008822a56 |
12 | 192106930b17 |
13 | 968261ac2cb |
14 | 47650c556dd |
15 | 24182a10157 |
hex | 1313fbd8543 |
1311034410307 has 2 divisors, whose sum is σ = 1311034410308. Its totient is φ = 1311034410306.
The previous prime is 1311034410299. The next prime is 1311034410341. The reversal of 1311034410307 is 7030144301131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311034410307 - 23 = 1311034410299 is a prime.
It is a super-2 number, since 2×13110344103072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311034410397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655517205153 + 655517205154.
It is an arithmetic number, because the mean of its divisors is an integer number (655517205154).
Almost surely, 21311034410307 is an apocalyptic number.
1311034410307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311034410307 is an equidigital number, since it uses as much as digits as its factorization.
1311034410307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 1311034410307 its reverse (7030144301131), we get a palindrome (8341178711438).
The spelling of 1311034410307 in words is "one trillion, three hundred eleven billion, thirty-four million, four hundred ten thousand, three hundred seven".
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