Base | Representation |
---|---|
bin | 1011111011000111111000… |
… | …0100111100111000010001 |
3 | 1201102100010012200102202020 |
4 | 2332301332010330320101 |
5 | 3204300001441231140 |
6 | 43514451504042053 |
7 | 2522122554220014 |
oct | 276617604747021 |
9 | 51370105612666 |
10 | 13110355414545 |
11 | 41a5085933034 |
12 | 1578a5b603329 |
13 | 7413bb9b5b8c |
14 | 33478a4c537b |
15 | 17b06ca876d0 |
hex | bec7e13ce11 |
13110355414545 has 16 divisors (see below), whose sum is σ = 21083048712000. Its totient is φ = 6956696204864.
The previous prime is 13110355414537. The next prime is 13110355414549. The reversal of 13110355414545 is 54541455301131.
It is a cyclic number.
It is not a de Polignac number, because 13110355414545 - 23 = 13110355414537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13110355414497 and 13110355414506.
It is not an unprimeable number, because it can be changed into a prime (13110355414549) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2218331295 + ... + 2218337204.
It is an arithmetic number, because the mean of its divisors is an integer number (1317690544500).
Almost surely, 213110355414545 is an apocalyptic number.
13110355414545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13110355414545 is a deficient number, since it is larger than the sum of its proper divisors (7972693297455).
13110355414545 is a wasteful number, since it uses less digits than its factorization.
13110355414545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4436668704.
The product of its (nonzero) digits is 360000, while the sum is 42.
The spelling of 13110355414545 in words is "thirteen trillion, one hundred ten billion, three hundred fifty-five million, four hundred fourteen thousand, five hundred forty-five".
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