Base | Representation |
---|---|
bin | 1011111011000111111000… |
… | …0100111110011110011011 |
3 | 1201102100010012200202201101 |
4 | 2332301332010332132123 |
5 | 3204300001441433313 |
6 | 43514451504132231 |
7 | 2522122554245044 |
oct | 276617604763633 |
9 | 51370105622641 |
10 | 13110355421083 |
11 | 41a5085937a38 |
12 | 1578a5b607077 |
13 | 7413bb9b8b4b |
14 | 33478a4c78cb |
15 | 17b06ca895dd |
hex | bec7e13e79b |
13110355421083 has 2 divisors, whose sum is σ = 13110355421084. Its totient is φ = 13110355421082.
The previous prime is 13110355421077. The next prime is 13110355421159. The reversal of 13110355421083 is 38012455301131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13110355421083 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110355421003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555177710541 + 6555177710542.
It is an arithmetic number, because the mean of its divisors is an integer number (6555177710542).
Almost surely, 213110355421083 is an apocalyptic number.
13110355421083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110355421083 is an equidigital number, since it uses as much as digits as its factorization.
13110355421083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 37.
The spelling of 13110355421083 in words is "thirteen trillion, one hundred ten billion, three hundred fifty-five million, four hundred twenty-one thousand, eighty-three".
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