Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0110110100111100110011 |
3 | 1201102100020110102102220221 |
4 | 2332302000312310330303 |
5 | 3204300100410344244 |
6 | 43514500251313511 |
7 | 2522123661445042 |
oct | 276620066647463 |
9 | 51370213372827 |
10 | 13110402043699 |
11 | 41a50aa191224 |
12 | 1578a7314b897 |
13 | 7413c8560bac |
14 | 334792782559 |
15 | 17b071be8784 |
hex | bec80db4f33 |
13110402043699 has 2 divisors, whose sum is σ = 13110402043700. Its totient is φ = 13110402043698.
The previous prime is 13110402043693. The next prime is 13110402043721. The reversal of 13110402043699 is 99634020401131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13110402043699 - 29 = 13110402043187 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110402043693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555201021849 + 6555201021850.
It is an arithmetic number, because the mean of its divisors is an integer number (6555201021850).
Almost surely, 213110402043699 is an apocalyptic number.
13110402043699 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110402043699 is an equidigital number, since it uses as much as digits as its factorization.
13110402043699 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 43.
The spelling of 13110402043699 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-three thousand, six hundred ninety-nine".
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