Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …1100001010111011001111 |
3 | 1201102100020120001121100220 |
4 | 2332302000330022323033 |
5 | 3204300101240210211 |
6 | 43514500341322423 |
7 | 2522124006400566 |
oct | 276620074127317 |
9 | 51370216047326 |
10 | 13110403444431 |
11 | 41a50aaa58657 |
12 | 1578a73706413 |
13 | 7413c8931627 |
14 | 334792a28bdd |
15 | 17b071dc3806 |
hex | bec80f0aecf |
13110403444431 has 16 divisors (see below), whose sum is σ = 17572642533504. Its totient is φ = 8694282878624.
The previous prime is 13110403444409. The next prime is 13110403444441. The reversal of 13110403444431 is 13444430401131.
It is a cyclic number.
It is not a de Polignac number, because 13110403444431 - 214 = 13110403428047 is a prime.
It is a super-2 number, since 2×131104034444312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13110403444392 and 13110403444401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110403444441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7484736 + ... + 9068741.
It is an arithmetic number, because the mean of its divisors is an integer number (1098290158344).
Almost surely, 213110403444431 is an apocalyptic number.
13110403444431 is a deficient number, since it is larger than the sum of its proper divisors (4462239089073).
13110403444431 is a wasteful number, since it uses less digits than its factorization.
13110403444431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16554870.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 13110403444431 its reverse (13444430401131), we get a palindrome (26554833845562).
The spelling of 13110403444431 in words is "thirteen trillion, one hundred ten billion, four hundred three million, four hundred forty-four thousand, four hundred thirty-one".
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