Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …1110110011100001111010 |
3 | 1201102100020121100200200210 |
4 | 2332302000332303201322 |
5 | 3204300101424310114 |
6 | 43514500404211550 |
7 | 2522124015305163 |
oct | 276620076634172 |
9 | 51370217320623 |
10 | 13110404135034 |
11 | 41a510038a4a8 |
12 | 1578a73999bb6 |
13 | 7413c8b13a7b |
14 | 334792b6876a |
15 | 17b071ead259 |
hex | bec80fb387a |
13110404135034 has 16 divisors (see below), whose sum is σ = 26256098734272. Its totient is φ = 4364252967648.
The previous prime is 13110404135021. The next prime is 13110404135039. The reversal of 13110404135034 is 43053140401131.
It is a junction number, because it is equal to n+sod(n) for n = 13110404134992 and 13110404135010.
It is not an unprimeable number, because it can be changed into a prime (13110404135039) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1470431179 + ... + 1470440094.
It is an arithmetic number, because the mean of its divisors is an integer number (1641006170892).
Almost surely, 213110404135034 is an apocalyptic number.
13110404135034 is an abundant number, since it is smaller than the sum of its proper divisors (13145694599238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110404135034 is a wasteful number, since it uses less digits than its factorization.
13110404135034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2940872021.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 13110404135034 its reverse (43053140401131), we get a palindrome (56163544536165).
The spelling of 13110404135034 in words is "thirteen trillion, one hundred ten billion, four hundred four million, one hundred thirty-five thousand, thirty-four".
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