Base | Representation |
---|---|
bin | 1011111011001000000110… |
… | …0101101100110101101011 |
3 | 1201102100021022112201021011 |
4 | 2332302001211230311223 |
5 | 3204300112032044433 |
6 | 43514501410524351 |
7 | 2522124201052555 |
oct | 276620145546553 |
9 | 51370238481234 |
10 | 13110414331243 |
11 | 41a5106114019 |
12 | 1578a772966b7 |
13 | 7413cac73a28 |
14 | 3347942604d5 |
15 | 17b072d243cd |
hex | bec8196cd6b |
13110414331243 has 8 divisors (see below), whose sum is σ = 13118676810320. Its totient is φ = 13102152343200.
The previous prime is 13110414331129. The next prime is 13110414331253. The reversal of 13110414331243 is 34213341401131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13110414331243 - 237 = 12972975377771 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13110414331253) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63647968 + ... + 63853618.
It is an arithmetic number, because the mean of its divisors is an integer number (1639834601290).
Almost surely, 213110414331243 is an apocalyptic number.
13110414331243 is a deficient number, since it is larger than the sum of its proper divisors (8262479077).
13110414331243 is a wasteful number, since it uses less digits than its factorization.
13110414331243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 245517.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 13110414331243 its reverse (34213341401131), we get a palindrome (47323755732374).
The spelling of 13110414331243 in words is "thirteen trillion, one hundred ten billion, four hundred fourteen million, three hundred thirty-one thousand, two hundred forty-three".
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