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13110443241131 is a prime number
BaseRepresentation
bin1011111011001000001101…
…0011111110111010101011
31201102100100022221111011202
42332302003103332322223
53204300141432204011
643514504322314415
72522125001561135
oct276620323767253
951370308844152
1013110443241131
1141a512046a495
121578a84ab8a0b
13741403c56782
14334798028055
1517b07563523b
hexbec834feeab

13110443241131 has 2 divisors, whose sum is σ = 13110443241132. Its totient is φ = 13110443241130.

The previous prime is 13110443241127. The next prime is 13110443241143. The reversal of 13110443241131 is 13114234401131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13110443241131 - 22 = 13110443241127 is a prime.

It is a super-2 number, since 2×131104432411312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13110443241094 and 13110443241103.

It is not a weakly prime, because it can be changed into another prime (13110443241191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555221620565 + 6555221620566.

It is an arithmetic number, because the mean of its divisors is an integer number (6555221620566).

Almost surely, 213110443241131 is an apocalyptic number.

13110443241131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110443241131 is an equidigital number, since it uses as much as digits as its factorization.

13110443241131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 13110443241131 its reverse (13114234401131), we get a palindrome (26224677642262).

The spelling of 13110443241131 in words is "thirteen trillion, one hundred ten billion, four hundred forty-three million, two hundred forty-one thousand, one hundred thirty-one".