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1311045240049 is a prime number
BaseRepresentation
bin10011000101000000011…
…000101100010011110001
311122100000222220210010221
4103011000120230103301
5132440010040140144
62442141425253041
7163501631445406
oct23050030542361
94570028823127
101311045240049
1146601394a556
1219210a494181
139682850173c
14476524742ad
152418394dd84
hex1314062c4f1

1311045240049 has 2 divisors, whose sum is σ = 1311045240050. Its totient is φ = 1311045240048.

The previous prime is 1311045240023. The next prime is 1311045240157. The reversal of 1311045240049 is 9400425401131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 839394954225 + 471650285824 = 916185^2 + 686768^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311045240049 - 227 = 1310911022321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311045239996 and 1311045240023.

It is not a weakly prime, because it can be changed into another prime (1311045240019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655522620024 + 655522620025.

It is an arithmetic number, because the mean of its divisors is an integer number (655522620025).

Almost surely, 21311045240049 is an apocalyptic number.

It is an amenable number.

1311045240049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311045240049 is an equidigital number, since it uses as much as digits as its factorization.

1311045240049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 34.

The spelling of 1311045240049 in words is "one trillion, three hundred eleven billion, forty-five million, two hundred forty thousand, forty-nine".