Base | Representation |
---|---|
bin | 10011000101000000011… |
… | …000101100010011110001 |
3 | 11122100000222220210010221 |
4 | 103011000120230103301 |
5 | 132440010040140144 |
6 | 2442141425253041 |
7 | 163501631445406 |
oct | 23050030542361 |
9 | 4570028823127 |
10 | 1311045240049 |
11 | 46601394a556 |
12 | 19210a494181 |
13 | 9682850173c |
14 | 476524742ad |
15 | 2418394dd84 |
hex | 1314062c4f1 |
1311045240049 has 2 divisors, whose sum is σ = 1311045240050. Its totient is φ = 1311045240048.
The previous prime is 1311045240023. The next prime is 1311045240157. The reversal of 1311045240049 is 9400425401131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 839394954225 + 471650285824 = 916185^2 + 686768^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311045240049 - 227 = 1310911022321 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311045239996 and 1311045240023.
It is not a weakly prime, because it can be changed into another prime (1311045240019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655522620024 + 655522620025.
It is an arithmetic number, because the mean of its divisors is an integer number (655522620025).
Almost surely, 21311045240049 is an apocalyptic number.
It is an amenable number.
1311045240049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311045240049 is an equidigital number, since it uses as much as digits as its factorization.
1311045240049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 1311045240049 in words is "one trillion, three hundred eleven billion, forty-five million, two hundred forty thousand, forty-nine".
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