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1311054313 is a prime number
BaseRepresentation
bin100111000100101…
…0001100111101001
310101100222110102011
41032021101213221
510141112214223
6334032235521
744326530532
oct11611214751
93340873364
101311054313
11613068568
1230709bba1
1317b8086aa
14c619b689
157a17580d
hex4e2519e9

1311054313 has 2 divisors, whose sum is σ = 1311054314. Its totient is φ = 1311054312.

The previous prime is 1311054271. The next prime is 1311054317. The reversal of 1311054313 is 3134501131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1055470144 + 255584169 = 32488^2 + 15987^2 .

It is an emirp because it is prime and its reverse (3134501131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311054313 - 221 = 1308957161 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311054317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655527156 + 655527157.

It is an arithmetic number, because the mean of its divisors is an integer number (655527157).

Almost surely, 21311054313 is an apocalyptic number.

It is an amenable number.

1311054313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311054313 is an equidigital number, since it uses as much as digits as its factorization.

1311054313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 1311054313 is about 36208.4839920149. The cubic root of 1311054313 is about 1094.4776427533.

Adding to 1311054313 its reverse (3134501131), we get a palindrome (4445555444).

The spelling of 1311054313 in words is "one billion, three hundred eleven million, fifty-four thousand, three hundred thirteen".