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1311056532553 = 5419241936987
BaseRepresentation
bin10011000101000001000…
…011110001010001001001
311122100001210011111112211
4103011001003301101021
5132440020433020203
62442142511305121
7163502126440225
oct23050103612111
94570053144484
101311056532553
1146601a2627a9
1219211221b1a1
139682a9566b1
1447653b73785
152418492ec6d
hex131410f1449

1311056532553 has 4 divisors (see below), whose sum is σ = 1311298474960. Its totient is φ = 1310814590148.

The previous prime is 1311056532503. The next prime is 1311056532601. The reversal of 1311056532553 is 3552356501131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311056532553 - 213 = 1311056524361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311056532503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120963075 + ... + 120973912.

It is an arithmetic number, because the mean of its divisors is an integer number (327824618740).

Almost surely, 21311056532553 is an apocalyptic number.

It is an amenable number.

1311056532553 is a deficient number, since it is larger than the sum of its proper divisors (241942407).

1311056532553 is an equidigital number, since it uses as much as digits as its factorization.

1311056532553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 241942406.

The product of its (nonzero) digits is 202500, while the sum is 40.

The spelling of 1311056532553 in words is "one trillion, three hundred eleven billion, fifty-six million, five hundred thirty-two thousand, five hundred fifty-three".

Divisors: 1 5419 241936987 1311056532553