Base | Representation |
---|---|
bin | 10011000101000001010… |
… | …110000001000111001001 |
3 | 11122100002010011112021001 |
4 | 103011001112001013021 |
5 | 132440023144103131 |
6 | 2442143202015001 |
7 | 163502215212241 |
oct | 23050126010711 |
9 | 4570063145231 |
10 | 1311061316041 |
11 | 466021a2a6a4 |
12 | 192113947461 |
13 | 9682b93ca69 |
14 | 4765465ab21 |
15 | 24185077261 |
hex | 131415811c9 |
1311061316041 has 2 divisors, whose sum is σ = 1311061316042. Its totient is φ = 1311061316040.
The previous prime is 1311061316017. The next prime is 1311061316083. The reversal of 1311061316041 is 1406131601131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1079512688016 + 231548628025 = 1038996^2 + 481195^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311061316041 - 27 = 1311061315913 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311061316441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655530658020 + 655530658021.
It is an arithmetic number, because the mean of its divisors is an integer number (655530658021).
Almost surely, 21311061316041 is an apocalyptic number.
It is an amenable number.
1311061316041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311061316041 is an equidigital number, since it uses as much as digits as its factorization.
1311061316041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 28.
Adding to 1311061316041 its reverse (1406131601131), we get a palindrome (2717192917172).
The spelling of 1311061316041 in words is "one trillion, three hundred eleven billion, sixty-one million, three hundred sixteen thousand, forty-one".
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