Base | Representation |
---|---|
bin | 10011000101000001011… |
… | …001100111101011011001 |
3 | 11122100002011221111201211 |
4 | 103011001121213223121 |
5 | 132440023414313231 |
6 | 2442143234143121 |
7 | 163502226224503 |
oct | 23050131475331 |
9 | 4570064844654 |
10 | 1311062260441 |
11 | 46602251519a |
12 | 192114121aa1 |
13 | 9682bbb088b |
14 | 47654824d73 |
15 | 241851b1eb1 |
hex | 13141667ad9 |
1311062260441 has 2 divisors, whose sum is σ = 1311062260442. Its totient is φ = 1311062260440.
The previous prime is 1311062260433. The next prime is 1311062260583. The reversal of 1311062260441 is 1440622601131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1279884942400 + 31177318041 = 1131320^2 + 176571^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311062260441 - 23 = 1311062260433 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311062260421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655531130220 + 655531130221.
It is an arithmetic number, because the mean of its divisors is an integer number (655531130221).
Almost surely, 21311062260441 is an apocalyptic number.
It is an amenable number.
1311062260441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311062260441 is an equidigital number, since it uses as much as digits as its factorization.
1311062260441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 1311062260441 its reverse (1440622601131), we get a palindrome (2751684861572).
The spelling of 1311062260441 in words is "one trillion, three hundred eleven billion, sixty-two million, two hundred sixty thousand, four hundred forty-one".
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