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13110937459513 is a prime number
BaseRepresentation
bin1011111011001010000011…
…0001010001101100111001
31201102101121202220101100021
42332302200301101230321
53204302144442201023
643515025335210441
72522143152425065
oct276624061215471
951371552811307
1013110937459513
1141a5354438033
121578ba2516a21
1374148246609a
14334803916aa5
1517b0a3c0a35d
hexbeca0c51b39

13110937459513 has 2 divisors, whose sum is σ = 13110937459514. Its totient is φ = 13110937459512.

The previous prime is 13110937459481. The next prime is 13110937459519. The reversal of 13110937459513 is 31595473901131.

13110937459513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12990315307264 + 120622152249 = 3604208^2 + 347307^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110937459513 - 25 = 13110937459481 is a prime.

It is a super-2 number, since 2×131109374595132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13110937459519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555468729756 + 6555468729757.

It is an arithmetic number, because the mean of its divisors is an integer number (6555468729757).

Almost surely, 213110937459513 is an apocalyptic number.

It is an amenable number.

13110937459513 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110937459513 is an equidigital number, since it uses as much as digits as its factorization.

13110937459513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1530900, while the sum is 52.

The spelling of 13110937459513 in words is "thirteen trillion, one hundred ten billion, nine hundred thirty-seven million, four hundred fifty-nine thousand, five hundred thirteen".