Base | Representation |
---|---|
bin | 111101000011011000… |
… | …1000100111100001001 |
3 | 110112102021122200001021 |
4 | 1322012301010330021 |
5 | 4122003131443423 |
6 | 140121530552441 |
7 | 12321012606445 |
oct | 1720661047411 |
9 | 415367580037 |
10 | 131110031113 |
11 | 50670215a16 |
12 | 214b0598721 |
13 | c495b58289 |
14 | 64baa99825 |
15 | 362552b95d |
hex | 1e86c44f09 |
131110031113 has 16 divisors (see below), whose sum is σ = 137384121600. Its totient is φ = 125018974080.
The previous prime is 131110031111. The next prime is 131110031131. The reversal of 131110031113 is 311130011131.
It is a cyclic number.
It is not a de Polignac number, because 131110031113 - 21 = 131110031111 is a prime.
It is a super-3 number, since 3×1311100311133 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131110031111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85503 + ... + 519163.
It is an arithmetic number, because the mean of its divisors is an integer number (8586507600).
Almost surely, 2131110031113 is an apocalyptic number.
It is an amenable number.
131110031113 is a deficient number, since it is larger than the sum of its proper divisors (6274090487).
131110031113 is an equidigital number, since it uses as much as digits as its factorization.
131110031113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 433872.
The product of its (nonzero) digits is 27, while the sum is 16.
Adding to 131110031113 its reverse (311130011131), we get a palindrome (442240042244).
The spelling of 131110031113 in words is "one hundred thirty-one billion, one hundred ten million, thirty-one thousand, one hundred thirteen".
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