Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …101110101110100010011 |
3 | 11122100011220001120002021 |
4 | 103011003231311310103 |
5 | 132440113341200132 |
6 | 2442151143032311 |
7 | 163503210414160 |
oct | 23050355656423 |
9 | 4570156046067 |
10 | 1311101115667 |
11 | 466042443752 |
12 | 19212513b697 |
13 | 96836c66335 |
14 | 47659a5b067 |
15 | 241887d9997 |
hex | 13143b75d13 |
1311101115667 has 4 divisors (see below), whose sum is σ = 1498401275056. Its totient is φ = 1123800956280.
The previous prime is 1311101115661. The next prime is 1311101115683. The reversal of 1311101115667 is 7665111011131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311101115667 - 219 = 1311100591379 is a prime.
It is a super-2 number, since 2×13111011156672 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1311101115661) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93650079684 + ... + 93650079697.
It is an arithmetic number, because the mean of its divisors is an integer number (374600318764).
Almost surely, 21311101115667 is an apocalyptic number.
1311101115667 is a deficient number, since it is larger than the sum of its proper divisors (187300159389).
1311101115667 is an equidigital number, since it uses as much as digits as its factorization.
1311101115667 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 187300159388.
The product of its (nonzero) digits is 3780, while the sum is 34.
Adding to 1311101115667 its reverse (7665111011131), we get a palindrome (8976212126798).
The spelling of 1311101115667 in words is "one trillion, three hundred eleven billion, one hundred one million, one hundred fifteen thousand, six hundred sixty-seven".
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