Base | Representation |
---|---|
bin | 100111000100101… |
… | …1101010111100001 |
3 | 10101101001220102101 |
4 | 1032021131113201 |
5 | 10141120234213 |
6 | 334033250401 |
7 | 44330121034 |
oct | 11611352741 |
9 | 3341056371 |
10 | 1311102433 |
11 | 6130a0733 |
12 | 307103a01 |
13 | 17b824574 |
14 | c61b101b |
15 | 7a184bdd |
hex | 4e25d5e1 |
1311102433 has 2 divisors, whose sum is σ = 1311102434. Its totient is φ = 1311102432.
The previous prime is 1311102427. The next prime is 1311102473. The reversal of 1311102433 is 3342011131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 748131904 + 562970529 = 27352^2 + 23727^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311102433 - 29 = 1311101921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1311102433.
It is not a weakly prime, because it can be changed into another prime (1311102473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551216 + 655551217.
It is an arithmetic number, because the mean of its divisors is an integer number (655551217).
Almost surely, 21311102433 is an apocalyptic number.
It is an amenable number.
1311102433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311102433 is an equidigital number, since it uses as much as digits as its factorization.
1311102433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
The square root of 1311102433 is about 36209.1484710701. The cubic root of 1311102433 is about 1094.4910328978.
Adding to 1311102433 its reverse (3342011131), we get a palindrome (4653113564).
The spelling of 1311102433 in words is "one billion, three hundred eleven million, one hundred two thousand, four hundred thirty-three".
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