1311103332321 has 4 divisors (see below), whose sum is σ = 1748137776432. Its totient is φ = 874068888212.

The previous prime is 1311103332277. The next prime is 1311103332349. The reversal of 1311103332321 is 1232333011131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311103332321 - 2⁷ = 1311103332193 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311103332291 and 1311103332300.

It is not an unprimeable number, because it can be changed into a prime (1311103332521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218517222051 + ... + 218517222056.

It is an arithmetic number, because the mean of its divisors is an integer number (437034444108).

Almost surely, 2^{1311103332321} is an apocalyptic number.

It is an amenable number.

1311103332321 is a deficient number, since it is larger than the sum of its proper divisors (437034444111).

1311103332321 is an equidigital number, since it uses as much as digits as its factorization.

1311103332321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437034444110.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 1311103332321 its reverse (1232333011131), we get a palindrome (2543436343452).

The spelling of 1311103332321 in words is "one trillion, three hundred eleven billion, one hundred three million, three hundred thirty-two thousand, three hundred twenty-one".