Base | Representation |
---|---|
bin | 1011111011001011000100… |
… | …0101111001110100011011 |
3 | 1201102102022212012000211221 |
4 | 2332302301011321310123 |
5 | 3204303230043132141 |
6 | 43515112440432511 |
7 | 2522153016152143 |
oct | 276626105716433 |
9 | 51372285160757 |
10 | 13111211302171 |
11 | 41a5484a76084 |
12 | 157905a178737 |
13 | 7414c7105c68 |
14 | 33482c03b923 |
15 | 17b0bcc9dbd1 |
hex | becb1179d1b |
13111211302171 has 2 divisors, whose sum is σ = 13111211302172. Its totient is φ = 13111211302170.
The previous prime is 13111211302093. The next prime is 13111211302253. The reversal of 13111211302171 is 17120311211131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13111211302171 - 229 = 13110674431259 is a prime.
It is not a weakly prime, because it can be changed into another prime (13111211302571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555605651085 + 6555605651086.
It is an arithmetic number, because the mean of its divisors is an integer number (6555605651086).
Almost surely, 213111211302171 is an apocalyptic number.
13111211302171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111211302171 is an equidigital number, since it uses as much as digits as its factorization.
13111211302171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 25.
The spelling of 13111211302171 in words is "thirteen trillion, one hundred eleven billion, two hundred eleven million, three hundred two thousand, one hundred seventy-one".
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