13111214001 has 4 divisors (see below), whose sum is σ = 17481618672. Its totient is φ = 8740809332.

The previous prime is 13111213957. The next prime is 13111214023. The reversal of 13111214001 is 10041211131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13111214001 - 2⁶ = 13111213937 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13111114001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185202331 + ... + 2185202336.

It is an arithmetic number, because the mean of its divisors is an integer number (4370404668).

Almost surely, 2^13111214001 is an apocalyptic number.

It is an amenable number.

13111214001 is a deficient number, since it is larger than the sum of its proper divisors (4370404671).

13111214001 is an equidigital number, since it uses as much as digits as its factorization.

13111214001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4370404670.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 13111214001 its reverse (10041211131), we get a palindrome (23152425132).

The spelling of 13111214001 in words is "thirteen billion, one hundred eleven million, two hundred fourteen thousand, one".