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13111220201 = 14851882851
BaseRepresentation
bin11000011010111110…
…10101011111101001
31020211202001222220012
430031133111133221
5203322433021301
610005002541305
7642623350532
oct141537253751
936752058805
1013111220201
115618a3a882
12265ab07835
13130c443581
148c543b689
1551b0c0ebb
hex30d7d57e9

13111220201 has 4 divisors (see below), whose sum is σ = 13112117904. Its totient is φ = 13110322500.

The previous prime is 13111220191. The next prime is 13111220231. The reversal of 13111220201 is 10202211131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111220201 is a prime.

It is a super-2 number, since 2×131112202012 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13111220231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 426575 + ... + 456276.

It is an arithmetic number, because the mean of its divisors is an integer number (3278029476).

Almost surely, 213111220201 is an apocalyptic number.

It is an amenable number.

13111220201 is a deficient number, since it is larger than the sum of its proper divisors (897703).

13111220201 is an equidigital number, since it uses as much as digits as its factorization.

13111220201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 897702.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 13111220201 its reverse (10202211131), we get a palindrome (23313431332).

The spelling of 13111220201 in words is "thirteen billion, one hundred eleven million, two hundred twenty thousand, two hundred one".

Divisors: 1 14851 882851 13111220201