Base | Representation |
---|---|
bin | 1011111011001011001001… |
… | …0010001100011001111011 |
3 | 1201102102101020211002102022 |
4 | 2332302302102030121323 |
5 | 3204303300203114433 |
6 | 43515114433225055 |
7 | 2522153351145365 |
oct | 276626222143173 |
9 | 51372336732368 |
10 | 13111231301243 |
11 | 41a5495295739 |
12 | 1579064a0218b |
13 | 7414cb2b8b2a |
14 | 334830965d35 |
15 | 17b0be8ee698 |
hex | becb248c67b |
13111231301243 has 2 divisors, whose sum is σ = 13111231301244. Its totient is φ = 13111231301242.
The previous prime is 13111231301167. The next prime is 13111231301261. The reversal of 13111231301243 is 34210313211131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111231301243 - 238 = 12836353394299 is a prime.
It is a super-2 number, since 2×131112313012432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13111231301543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555615650621 + 6555615650622.
It is an arithmetic number, because the mean of its divisors is an integer number (6555615650622).
Almost surely, 213111231301243 is an apocalyptic number.
13111231301243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111231301243 is an equidigital number, since it uses as much as digits as its factorization.
13111231301243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 13111231301243 its reverse (34210313211131), we get a palindrome (47321544512374).
The spelling of 13111231301243 in words is "thirteen trillion, one hundred eleven billion, two hundred thirty-one million, three hundred one thousand, two hundred forty-three".
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