13111244030002 has 4 divisors (see below), whose sum is σ = 19666866045006. Its totient is φ = 6555622015000.

The previous prime is 13111244029979. The next prime is 13111244030029. The reversal of 13111244030002 is 20003044211131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12695888270641 + 415355759361 = 3563129^2 + 644481^2 .

It is a super-2 number, since 2×13111244030002² (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277811007499 + ... + 3277811007502.

Almost surely, 2^{13111244030002} is an apocalyptic number.

13111244030002 is a deficient number, since it is larger than the sum of its proper divisors (6555622015004).

13111244030002 is an equidigital number, since it uses as much as digits as its factorization.

13111244030002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6555622015003.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13111244030002 its reverse (20003044211131), we get a palindrome (33114288241133).

The spelling of 13111244030002 in words is "thirteen trillion, one hundred eleven billion, two hundred forty-four million, thirty thousand, two".