Base | Representation |
---|---|
bin | 1011111011001011011010… |
… | …0000101010011110111011 |
3 | 1201102102120012020021210021 |
4 | 2332302312200222132323 |
5 | 3204303421331001243 |
6 | 43515125445031311 |
7 | 2522155201620112 |
oct | 276626640523673 |
9 | 51372505207707 |
10 | 13111302203323 |
11 | 41a55213124a5 |
12 | 15790846b5537 |
13 | 74150cbb211c |
14 | 33483a140c79 |
15 | 17b0c5c576ed |
hex | becb682a7bb |
13111302203323 has 4 divisors (see below), whose sum is σ = 13801370740360. Its totient is φ = 12421233666288.
The previous prime is 13111302203317. The next prime is 13111302203339. The reversal of 13111302203323 is 32330220311131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13111302203323 - 229 = 13110765332411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13111302203383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345034268490 + ... + 345034268527.
It is an arithmetic number, because the mean of its divisors is an integer number (3450342685090).
Almost surely, 213111302203323 is an apocalyptic number.
13111302203323 is a deficient number, since it is larger than the sum of its proper divisors (690068537037).
13111302203323 is an equidigital number, since it uses as much as digits as its factorization.
13111302203323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 690068537036.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13111302203323 its reverse (32330220311131), we get a palindrome (45441522514454).
The spelling of 13111302203323 in words is "thirteen trillion, one hundred eleven billion, three hundred two million, two hundred three thousand, three hundred twenty-three".
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