Base | Representation |
---|---|
bin | 1011111011001011011110… |
… | …1100101001010001100001 |
3 | 1201102102121120201020010121 |
4 | 2332302313230221101201 |
5 | 3204303441430340223 |
6 | 43515131440000241 |
7 | 2522155533125053 |
oct | 276626754512141 |
9 | 51372546636117 |
10 | 13111322121313 |
11 | 41a5531587149 |
12 | 157908b300081 |
13 | 741514067110 |
14 | 33483ca478d3 |
15 | 17b0c788e15d |
hex | becb7b29461 |
13111322121313 has 16 divisors (see below), whose sum is σ = 14181147017856. Its totient is φ = 12050253740160.
The previous prime is 13111322121301. The next prime is 13111322121319. The reversal of 13111322121313 is 31312122311131.
It is a cyclic number.
It is not a de Polignac number, because 13111322121313 - 217 = 13111321990241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13111322121319) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73791606 + ... + 73969072.
It is an arithmetic number, because the mean of its divisors is an integer number (886321688616).
Almost surely, 213111322121313 is an apocalyptic number.
13111322121313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13111322121313 is a deficient number, since it is larger than the sum of its proper divisors (1069824896543).
13111322121313 is a wasteful number, since it uses less digits than its factorization.
13111322121313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202104.
The product of its digits is 648, while the sum is 25.
Adding to 13111322121313 its reverse (31312122311131), we get a palindrome (44423444432444).
The spelling of 13111322121313 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-two million, one hundred twenty-one thousand, three hundred thirteen".
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