1311140033201 has 4 divisors (see below), whose sum is σ = 1329606794304. Its totient is φ = 1292673272100.

The previous prime is 1311140033129. The next prime is 1311140033263. The reversal of 1311140033201 is 1023300411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311140033201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311140033101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9233380445 + ... + 9233380586.

It is an arithmetic number, because the mean of its divisors is an integer number (332401698576).

Almost surely, 2^{1311140033201} is an apocalyptic number.

It is an amenable number.

1311140033201 is a deficient number, since it is larger than the sum of its proper divisors (18466761103).

1311140033201 is an equidigital number, since it uses as much as digits as its factorization.

1311140033201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18466761102.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1311140033201 its reverse (1023300411131), we get a palindrome (2334440444332).

The spelling of 1311140033201 in words is "one trillion, three hundred eleven billion, one hundred forty million, thirty-three thousand, two hundred one".