Base | Representation |
---|---|
bin | 11000011011000000… |
… | …00111000100010001 |
3 | 1020211202110022102111 |
4 | 30031200013010101 |
5 | 203323011020444 |
6 | 10005011145321 |
7 | 642625154521 |
oct | 141540070421 |
9 | 36752408374 |
10 | 13111423249 |
11 | 5619069391 |
12 | 265aba5241 |
13 | 130c4b4b12 |
14 | 8c5491681 |
15 | 51b111234 |
hex | 30d807111 |
13111423249 has 2 divisors, whose sum is σ = 13111423250. Its totient is φ = 13111423248.
The previous prime is 13111423229. The next prime is 13111423253. The reversal of 13111423249 is 94232411131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13111395025 + 28224 = 114505^2 + 168^2 .
It is a cyclic number.
It is not a de Polignac number, because 13111423249 - 223 = 13103034641 is a prime.
It is a super-2 number, since 2×131114232492 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13111423249.
It is not a weakly prime, because it can be changed into another prime (13111423229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555711624 + 6555711625.
It is an arithmetic number, because the mean of its divisors is an integer number (6555711625).
Almost surely, 213111423249 is an apocalyptic number.
It is an amenable number.
13111423249 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111423249 is an equidigital number, since it uses as much as digits as its factorization.
13111423249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 31.
The spelling of 13111423249 in words is "thirteen billion, one hundred eleven million, four hundred twenty-three thousand, two hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •