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13111431322243 = 25751017242499
BaseRepresentation
bin1011111011001011111000…
…1101001101101010000011
31201102102220012012012122111
42332302332031031222003
53204304202404302433
643515150340320151
72522161330251112
oct276627615155203
951372805165574
1013111431322243
1141a5588192451
1215790bb9a3057
1374153087c857
1433484d351c79
1517b0d225edcd
hexbecbe34da83

13111431322243 has 4 divisors (see below), whose sum is σ = 13162448565000. Its totient is φ = 13060414079488.

The previous prime is 13111431322151. The next prime is 13111431322247. The reversal of 13111431322243 is 34222313411131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111431322243 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13111431322247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25508620993 + ... + 25508621506.

It is an arithmetic number, because the mean of its divisors is an integer number (3290612141250).

Almost surely, 213111431322243 is an apocalyptic number.

13111431322243 is a deficient number, since it is larger than the sum of its proper divisors (51017242757).

13111431322243 is an equidigital number, since it uses as much as digits as its factorization.

13111431322243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51017242756.

The product of its digits is 10368, while the sum is 31.

Adding to 13111431322243 its reverse (34222313411131), we get a palindrome (47333744733374).

The spelling of 13111431322243 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-one million, three hundred twenty-two thousand, two hundred forty-three".

Divisors: 1 257 51017242499 13111431322243