Base | Representation |
---|---|
bin | 11000011011000000… |
… | …01011111101111010 |
3 | 1020211202111022221221 |
4 | 30031200023331322 |
5 | 203323012141242 |
6 | 10005011422254 |
7 | 642625300165 |
oct | 141540137572 |
9 | 36752438857 |
10 | 13111443322 |
11 | 561908247a |
12 | 265abb498a |
13 | 130c4c0cb3 |
14 | 8c5498adc |
15 | 51b117167 |
hex | 30d80bf7a |
13111443322 has 4 divisors (see below), whose sum is σ = 19667164986. Its totient is φ = 6555721660.
The previous prime is 13111443311. The next prime is 13111443329. The reversal of 13111443322 is 22334411131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9590089041 + 3521354281 = 97929^2 + 59341^2 .
It is not an unprimeable number, because it can be changed into a prime (13111443329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277860829 + ... + 3277860832.
Almost surely, 213111443322 is an apocalyptic number.
13111443322 is a deficient number, since it is larger than the sum of its proper divisors (6555721664).
13111443322 is an equidigital number, since it uses as much as digits as its factorization.
13111443322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6555721663.
The product of its digits is 1728, while the sum is 25.
Adding to 13111443322 its reverse (22334411131), we get a palindrome (35445854453).
The spelling of 13111443322 in words is "thirteen billion, one hundred eleven million, four hundred forty-three thousand, three hundred twenty-two".
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