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13111501483 is a prime number
BaseRepresentation
bin11000011011000000…
…11010001010101011
31020211202121021202001
430031200122022223
5203323021021413
610005012551431
7642625631563
oct141540321253
936752537661
1013111501483
115619112143
12265b022577
13130c511602
148c54b1da3
1551b1294dd
hex30d81a2ab

13111501483 has 2 divisors, whose sum is σ = 13111501484. Its totient is φ = 13111501482.

The previous prime is 13111501441. The next prime is 13111501517. The reversal of 13111501483 is 38410511131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111501483 is a prime.

It is a super-2 number, since 2×131115014832 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13111501423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555750741 + 6555750742.

It is an arithmetic number, because the mean of its divisors is an integer number (6555750742).

Almost surely, 213111501483 is an apocalyptic number.

13111501483 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111501483 is an equidigital number, since it uses as much as digits as its factorization.

13111501483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 28.

The spelling of 13111501483 in words is "thirteen billion, one hundred eleven million, five hundred one thousand, four hundred eighty-three".