Base | Representation |
---|---|
bin | 11101110011111110100011… |
… | …100001001010100011000011 |
3 | 122012020111021102102101112120 |
4 | 131303332203201022203003 |
5 | 114141142422231301110 |
6 | 1142505255043055323 |
7 | 36421522063415616 |
oct | 3563764341124303 |
9 | 565214242371476 |
10 | 131115210025155 |
11 | 38860714990244 |
12 | 1285700a671543 |
13 | 582115a563935 |
14 | 245401d71c17d |
15 | 102591a4e8870 |
hex | 773fa384a8c3 |
131115210025155 has 16 divisors (see below), whose sum is σ = 209784841497504. Its totient is φ = 69927943527680.
The previous prime is 131115210025127. The next prime is 131115210025207. The reversal of 131115210025155 is 551520012511131.
It is not a de Polignac number, because 131115210025155 - 231 = 131113062541507 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3965226 + ... + 16671935.
It is an arithmetic number, because the mean of its divisors is an integer number (13111552593594).
Almost surely, 2131115210025155 is an apocalyptic number.
131115210025155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131115210025155 is a deficient number, since it is larger than the sum of its proper divisors (78669631472349).
131115210025155 is a wasteful number, since it uses less digits than its factorization.
131115210025155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21060726.
The product of its (nonzero) digits is 7500, while the sum is 33.
Adding to 131115210025155 its reverse (551520012511131), we get a palindrome (682635222536286).
The spelling of 131115210025155 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred ten million, twenty-five thousand, one hundred fifty-five".
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