Base | Representation |
---|---|
bin | 10011000101000111111… |
… | …110111010100100011001 |
3 | 11122100100212202102221012 |
4 | 103011013332322210121 |
5 | 132440240202403231 |
6 | 2442202221223305 |
7 | 163505040031142 |
oct | 23050776724431 |
9 | 4570325672835 |
10 | 1311172700441 |
11 | 46607989741a |
12 | 192145101b35 |
13 | 96848a3b2a6 |
14 | 47665372ac9 |
15 | 2418ec29e2b |
hex | 13147fba919 |
1311172700441 has 2 divisors, whose sum is σ = 1311172700442. Its totient is φ = 1311172700440.
The previous prime is 1311172700381. The next prime is 1311172700449. The reversal of 1311172700441 is 1440072711131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 958384218841 + 352788481600 = 978971^2 + 593960^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311172700441 - 218 = 1311172438297 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311172700398 and 1311172700407.
It is not a weakly prime, because it can be changed into another prime (1311172700449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655586350220 + 655586350221.
It is an arithmetic number, because the mean of its divisors is an integer number (655586350221).
Almost surely, 21311172700441 is an apocalyptic number.
It is an amenable number.
1311172700441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311172700441 is an equidigital number, since it uses as much as digits as its factorization.
1311172700441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4704, while the sum is 32.
The spelling of 1311172700441 in words is "one trillion, three hundred eleven billion, one hundred seventy-two million, seven hundred thousand, four hundred forty-one".
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