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13111956093547 is a prime number
BaseRepresentation
bin1011111011001101110101…
…1111000011101001101011
31201102111020202122100112201
42332303131133003221223
53204311241224443142
643515314404121031
72522210331605443
oct276633537035153
951374222570481
1013111956093547
1141a5827428943
121579227696177
137415b54c8a0c
1433489cd15123
1517b11336cab7
hexbecdd7c3a6b

13111956093547 has 2 divisors, whose sum is σ = 13111956093548. Its totient is φ = 13111956093546.

The previous prime is 13111956093517. The next prime is 13111956093637. The reversal of 13111956093547 is 74539065911131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111956093547 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111956093517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555978046773 + 6555978046774.

It is an arithmetic number, because the mean of its divisors is an integer number (6555978046774).

Almost surely, 213111956093547 is an apocalyptic number.

13111956093547 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111956093547 is an equidigital number, since it uses as much as digits as its factorization.

13111956093547 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3061800, while the sum is 55.

The spelling of 13111956093547 in words is "thirteen trillion, one hundred eleven billion, nine hundred fifty-six million, ninety-three thousand, five hundred forty-seven".