13112001102033 has 12 divisors (see below), whose sum is σ = 18952810879860. Its totient is φ = 8735216960736.

The previous prime is 13112001101987. The next prime is 13112001102043. The reversal of 13112001102033 is 33020110021131.

It can be written as a sum of positive squares in 2 ways, for example, as 1051223685264 + 12060777416769 = 1025292^2 + 3472863^2 .

It is a de Polignac number, because none of the positive numbers 2^k-13112001102033 is a prime.

It is a super-3 number, since 3×13112001102033³ (a number of 40 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13112001101997 and 13112001102015.

It is not an unprimeable number, because it can be changed into a prime (13112001102043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 509745366 + ... + 509771087.

It is an arithmetic number, because the mean of its divisors is an integer number (1579400906655).

Almost surely, 2^{13112001102033} is an apocalyptic number.

It is an amenable number.

13112001102033 is a deficient number, since it is larger than the sum of its proper divisors (5840809777827).

13112001102033 is a wasteful number, since it uses less digits than its factorization.

13112001102033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1019517888 (or 1019517885 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13112001102033 its reverse (33020110021131), we get a palindrome (46132111123164).

The spelling of 13112001102033 in words is "thirteen trillion, one hundred twelve billion, one million, one hundred two thousand, thirty-three".