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13112011301131 is a prime number
BaseRepresentation
bin1011111011001110000011…
…0001101010000100001011
31201102111101121112012010001
42332303200301222010023
53204311344343114011
643515324055303431
72522211602062501
oct276634061520413
951374347465101
1013112011301131
1141a5855606146
12157924207ab77
137415c3a88522
143348a63a6671
1517b1181257c1
hexbece0c6a10b

13112011301131 has 2 divisors, whose sum is σ = 13112011301132. Its totient is φ = 13112011301130.

The previous prime is 13112011301111. The next prime is 13112011301201. The reversal of 13112011301131 is 13110311021131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13112011301131 - 217 = 13112011170059 is a prime.

It is a super-2 number, since 2×131120113011312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112011301099 and 13112011301108.

It is not a weakly prime, because it can be changed into another prime (13112011301101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556005650565 + 6556005650566.

It is an arithmetic number, because the mean of its divisors is an integer number (6556005650566).

Almost surely, 213112011301131 is an apocalyptic number.

13112011301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112011301131 is an equidigital number, since it uses as much as digits as its factorization.

13112011301131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 13112011301131 its reverse (13110311021131), we get a palindrome (26222322322262).

The spelling of 13112011301131 in words is "thirteen trillion, one hundred twelve billion, eleven million, three hundred one thousand, one hundred thirty-one".