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131120233035404 = 221091492018352211
BaseRepresentation
bin11101110100000011001110…
…111010011011011010001100
3122012020222020111002202020012
4131310003032322123122030
5114141233214124113104
61142511445315412352
736422060415330434
oct3564031672333214
9565228214082205
10131120233035404
1138862862284188
1212857b908b40b8
13582177b0bab52
14245437888d2c4
151025b11497d6e
hex7740cee9b68c

131120233035404 has 24 divisors (see below), whose sum is σ = 233119680486000. Its totient is φ = 64522683449280.

The previous prime is 131120233035397. The next prime is 131120233035511. The reversal of 131120233035404 is 404530332021131.

It is a super-2 number, since 2×1311202330354042 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1009111142 + ... + 1009241069.

It is an arithmetic number, because the mean of its divisors is an integer number (9713320020250).

Almost surely, 2131120233035404 is an apocalyptic number.

It is an amenable number.

131120233035404 is a deficient number, since it is larger than the sum of its proper divisors (101999447450596).

131120233035404 is a wasteful number, since it uses less digits than its factorization.

131120233035404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2018352473 (or 2018352471 counting only the distinct ones).

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 131120233035404 its reverse (404530332021131), we get a palindrome (535650565056535).

The spelling of 131120233035404 in words is "one hundred thirty-one trillion, one hundred twenty billion, two hundred thirty-three million, thirty-five thousand, four hundred four".

Divisors: 1 2 4 109 149 218 298 436 596 16241 32482 64964 2018352211 4036704422 8073408844 220000390999 300734479439 440000781998 601468958878 880001563996 1202937917756 32780058258851 65560116517702 131120233035404