131120304213433 has 4 divisors (see below), whose sum is σ = 131140629797968. Its totient is φ = 131099978628900.

The previous prime is 131120304213397. The next prime is 131120304213439. The reversal of 131120304213433 is 334312403021131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131120304213433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131120304213395 and 131120304213404.

It is not an unprimeable number, because it can be changed into a prime (131120304213439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10162782591 + ... + 10162795492.

It is an arithmetic number, because the mean of its divisors is an integer number (32785157449492).

Almost surely, 2^{131120304213433} is an apocalyptic number.

It is an amenable number.

131120304213433 is a deficient number, since it is larger than the sum of its proper divisors (20325584535).

131120304213433 is an equidigital number, since it uses as much as digits as its factorization.

131120304213433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20325584534.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 131120304213433 its reverse (334312403021131), we get a palindrome (465432707234564).

The spelling of 131120304213433 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred four million, two hundred thirteen thousand, four hundred thirty-three".