131121110212033 has 8 divisors (see below), whose sum is σ = 131146117113600. Its totient is φ = 131096104474800.

The previous prime is 131121110212009. The next prime is 131121110212063. The reversal of 131121110212033 is 330212011121131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131121110212033 is a prime.

It is a super-2 number, since 2×131121110212033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131121110211995 and 131121110212013.

It is not an unprimeable number, because it can be changed into a prime (131121110212063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 244376016 + ... + 244911982.

It is an arithmetic number, because the mean of its divisors is an integer number (16393264639200).

Almost surely, 2^{131121110212033} is an apocalyptic number.

It is an amenable number.

131121110212033 is a deficient number, since it is larger than the sum of its proper divisors (25006901567).

131121110212033 is an equidigital number, since it uses as much as digits as its factorization.

131121110212033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 582167.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 131121110212033 its reverse (330212011121131), we get a palindrome (461333121333164).

The spelling of 131121110212033 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred ten million, two hundred twelve thousand, thirty-three".