Base | Representation |
---|---|
bin | 111101000011101101… |
… | …1010101110011011010 |
3 | 110112110001111112202002 |
4 | 1322013123111303122 |
5 | 4122014001011414 |
6 | 140123004241002 |
7 | 12321206022212 |
oct | 1720733256332 |
9 | 415401445662 |
10 | 131121110234 |
11 | 506764a2914 |
12 | 214b4240162 |
13 | c49823707a |
14 | 64bc341242 |
15 | 36264b94de |
hex | 1e876d5cda |
131121110234 has 4 divisors (see below), whose sum is σ = 196681665354. Its totient is φ = 65560555116.
The previous prime is 131121110203. The next prime is 131121110269. The reversal of 131121110234 is 432011121131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 111085557025 + 20035553209 = 333295^2 + 141547^2 .
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32780277557 + ... + 32780277560.
Almost surely, 2131121110234 is an apocalyptic number.
131121110234 is a deficient number, since it is larger than the sum of its proper divisors (65560555120).
131121110234 is an equidigital number, since it uses as much as digits as its factorization.
131121110234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65560555119.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 131121110234 its reverse (432011121131), we get a palindrome (563132231365).
The spelling of 131121110234 in words is "one hundred thirty-one billion, one hundred twenty-one million, one hundred ten thousand, two hundred thirty-four".
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