Base | Representation |
---|---|
bin | 1011111011001110011011… |
… | …0010111110011100001011 |
3 | 1201102111122122120222021021 |
4 | 2332303212302332130023 |
5 | 3204312101222410102 |
6 | 43515342104253311 |
7 | 2522214236456203 |
oct | 276634662763413 |
9 | 51374578528237 |
10 | 13112112310027 |
11 | 41a58a7626675 |
12 | 157926ba71237 |
13 | 74160b9932c3 |
14 | 3348b597b403 |
15 | 17b121e29137 |
hex | bece6cbe70b |
13112112310027 has 2 divisors, whose sum is σ = 13112112310028. Its totient is φ = 13112112310026.
The previous prime is 13112112309991. The next prime is 13112112310043. The reversal of 13112112310027 is 72001321121131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112112310027 - 211 = 13112112307979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13112112309983 and 13112112310010.
It is not a weakly prime, because it can be changed into another prime (13112112310127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556056155013 + 6556056155014.
It is an arithmetic number, because the mean of its divisors is an integer number (6556056155014).
Almost surely, 213112112310027 is an apocalyptic number.
13112112310027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112112310027 is an equidigital number, since it uses as much as digits as its factorization.
13112112310027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 13112112310027 its reverse (72001321121131), we get a palindrome (85113433431158).
The spelling of 13112112310027 in words is "thirteen trillion, one hundred twelve billion, one hundred twelve million, three hundred ten thousand, twenty-seven".
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