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131121123225137 is a prime number
BaseRepresentation
bin11101110100000100000011…
…111110001110111000110001
3122012021001112112011001222022
4131310010003332032320301
5114141242030021201022
61142512113515321225
736422121444656663
oct3564040376167061
9565231475131868
10131121123225137
1138863179815981
121285819aa50215
13582189065b136
142454420bb4533
151025b646d7c42
hex774103f8ee31

131121123225137 has 2 divisors, whose sum is σ = 131121123225138. Its totient is φ = 131121123225136.

The previous prime is 131121123225089. The next prime is 131121123225233. The reversal of 131121123225137 is 731522321121131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126374829622336 + 4746293602801 = 11241656^2 + 2178599^2 .

It is a cyclic number.

It is not a de Polignac number, because 131121123225137 - 222 = 131121119030833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131121123225097 and 131121123225106.

It is not a weakly prime, because it can be changed into another prime (131121123525137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560561612568 + 65560561612569.

It is an arithmetic number, because the mean of its divisors is an integer number (65560561612569).

Almost surely, 2131121123225137 is an apocalyptic number.

It is an amenable number.

131121123225137 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121123225137 is an equidigital number, since it uses as much as digits as its factorization.

131121123225137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15120, while the sum is 35.

Adding to 131121123225137 its reverse (731522321121131), we get a palindrome (862643444346268).

The spelling of 131121123225137 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred twenty-three million, two hundred twenty-five thousand, one hundred thirty-seven".