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1311212017 is a prime number
BaseRepresentation
bin100111000100111…
…1000000111110001
310101101021110202001
41032021320013301
510141132241032
6334035454001
744331055363
oct11611700761
93341243661
101311212017
11613165aa5
12307157301
1317b8623cb
14c61dcd33
157a1a73e7
hex4e2781f1

1311212017 has 2 divisors, whose sum is σ = 1311212018. Its totient is φ = 1311212016.

The previous prime is 1311212009. The next prime is 1311212041. The reversal of 1311212017 is 7102121131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1112289201 + 198922816 = 33351^2 + 14104^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311212017 - 23 = 1311212009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311211985 and 1311212003.

It is not a weakly prime, because it can be changed into another prime (1311212087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655606008 + 655606009.

It is an arithmetic number, because the mean of its divisors is an integer number (655606009).

Almost surely, 21311212017 is an apocalyptic number.

It is an amenable number.

1311212017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311212017 is an equidigital number, since it uses as much as digits as its factorization.

1311212017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

The square root of 1311212017 is about 36210.6616481942. The cubic root of 1311212017 is about 1094.5215251413.

Adding to 1311212017 its reverse (7102121131), we get a palindrome (8413333148).

The spelling of 1311212017 in words is "one billion, three hundred eleven million, two hundred twelve thousand, seventeen".