Base | Representation |
---|---|
bin | 1011111011001110011101… |
… | …0100001000010101110011 |
3 | 1201102111200020221112111102 |
4 | 2332303213110020111303 |
5 | 3204312110434020311 |
6 | 43515343014435015 |
7 | 2522214403365242 |
oct | 276634724102563 |
9 | 51374606845442 |
10 | 13112121001331 |
11 | 41a5901522570 |
12 | 1579272962a6b |
13 | 7416107172a1 |
14 | 3348b6ba0959 |
15 | 17b122a9443b |
hex | bece7508573 |
13112121001331 has 32 divisors (see below), whose sum is σ = 15072055207680. Its totient is φ = 11281436352000.
The previous prime is 13112121001283. The next prime is 13112121001391. The reversal of 13112121001331 is 13310012121131.
It is a de Polignac number, because none of the positive numbers 2k-13112121001331 is a prime.
It is a super-2 number, since 2×131121210013312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13112121001391) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1044534551 + ... + 1044547103.
It is an arithmetic number, because the mean of its divisors is an integer number (471001725240).
Almost surely, 213112121001331 is an apocalyptic number.
13112121001331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13112121001331 is a deficient number, since it is larger than the sum of its proper divisors (1959934206349).
13112121001331 is a wasteful number, since it uses less digits than its factorization.
13112121001331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17187.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 13112121001331 its reverse (13310012121131), we get a palindrome (26422133122462).
The spelling of 13112121001331 in words is "thirteen trillion, one hundred twelve billion, one hundred twenty-one million, one thousand, three hundred thirty-one".
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