Base | Representation |
---|---|
bin | 11101110100000100001010… |
… | …100101010011010101000011 |
3 | 122012021001211020211122011211 |
4 | 131310010022211103111003 |
5 | 114141242241414131433 |
6 | 1142512132520350551 |
7 | 36422124262441330 |
oct | 3564041245232503 |
9 | 565231736748154 |
10 | 131121234130243 |
11 | 38863226385595 |
12 | 12858210015457 |
13 | 58218aa61c466 |
14 | 2454431803987 |
15 | 1025b6e2e38cd |
hex | 77410a953543 |
131121234130243 has 4 divisors (see below), whose sum is σ = 149852839006000. Its totient is φ = 112389629254488.
The previous prime is 131121234130199. The next prime is 131121234130253. The reversal of 131121234130243 is 342031432121131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131121234130243 - 225 = 131121200575811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131121234130253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9365802437868 + ... + 9365802437881.
It is an arithmetic number, because the mean of its divisors is an integer number (37463209751500).
Almost surely, 2131121234130243 is an apocalyptic number.
131121234130243 is a deficient number, since it is larger than the sum of its proper divisors (18731604875757).
131121234130243 is an equidigital number, since it uses as much as digits as its factorization.
131121234130243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18731604875756.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 131121234130243 its reverse (342031432121131), we get a palindrome (473152666251374).
The spelling of 131121234130243 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two hundred thirty-four million, one hundred thirty thousand, two hundred forty-three".
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