131121401 has 4 divisors (see below), whose sum is σ = 131145552. Its totient is φ = 131097252.

The previous prime is 131121379. The next prime is 131121409. The reversal of 131121401 is 104121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104121131 = 79 ⋅1317989.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131121401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131121409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290 + ... + 16196.

It is an arithmetic number, because the mean of its divisors is an integer number (32786388).

Almost surely, 2^131121401 is an apocalyptic number.

It is an amenable number.

131121401 is a deficient number, since it is larger than the sum of its proper divisors (24151).

131121401 is an equidigital number, since it uses as much as digits as its factorization.

131121401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24150.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 131121401 is about 11450.8253414328. The cubic root of 131121401 is about 508.0321463217.

Adding to 131121401 its reverse (104121131), we get a palindrome (235242532).

The spelling of 131121401 in words is "one hundred thirty-one million, one hundred twenty-one thousand, four hundred one".